Wayne Arthurs vs Hyung Taik Lee — Indianapolis Round of 64
Indianapolis · ATP · Round of 64
2 — 0
Sets
Monday, 12 August 2002 ·
hard
Arthurs W.6-4 6-3
Taik Lee H.
Arthurs W.
662
Taik Lee H.
430
Wayne Arthurs defeated Hyung Taik Lee 6-4 6-3 in the Indianapolis round of 64 on hard. The upset overturned the form book — Hyung Taik Lee came in leading the head-to-head 1–0. Wayne Arthurs claimed a first win over Hyung Taik Lee in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Wayne Arthurs closed it out in two sets, 6–4 6–3.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2004-10-04 | Tokyo | R32 | hard | Hyung Taik Lee | 6-2 7-6 |
Statistics
This season1st serve in·Slight edge
57%
64%
1st serve points won·Clear edge
81%
69%
2nd serve points won·Even
54%
52%
Service points won·Slight edge
69%
62%
Return points won·Slight edge
29%
37%
Break points saved·Slight edge
67%
58%
Aces / match·Dominant
16.0
3.3
Double faults / match·Dominant
5.2
2.0
Averages over each player's completed matches in the selected window (167 vs 200). ATP, WTA & Challenger.