Anne Kremer vs Petra Mandula — Indian Wells Round of 64
Indian Wells · WTA · Round of 64
2 — 1
Sets
Wednesday, 6 March 2002 ·
hard
Kremer A.4-6 6-3 6-3
Mandula P.
Kremer A.
4662
Mandula P.
6331
Anne Kremer defeated Petra Mandula 4-6 6-3 6-3 in the Indian Wells round of 64 on hard. The result followed the form book — Anne Kremer came in leading the head-to-head 2–1, defending last year's round of 32. Anne Kremer extended the head-to-head to 3–1.
Key context
- Match story: Anne Kremer dropped the opening set before beating Petra Mandula 4–6 6–3 6–3.
Head to head
2–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2001-04-16 | Budapest | QF | clay | Anne Kremer | 2-6 7-6 6-1 |
| 1998-12-07 | Bad Gogging 50K | R32 | carpet | Petra Mandula | 6-1 2-6 7-5 |
| 1998-10-19 | Welwyn 25K | R32 | carpet | Anne Kremer | 7-5 4-6 7-5 |
Statistics
This season1st serve in·Slight edge
67%
60%
1st serve points won·Slight edge
55%
61%
2nd serve points won·Even
41%
45%
Service points won·Slight edge
50%
55%
Return points won·Slight edge
42%
47%
Break points saved·Slight edge
46%
56%
Aces / match·Even
1.3
0.9
Double faults / match·Dominant
3.0
6.3
Averages over each player's completed matches in the selected window (41 vs 15). ATP, WTA & Challenger.
Conditions
Court speed
Medium-slowfavours grinders
SlowFast