Tatiana Panova vs Alicia Molik — Australian Open Round of 128
Australian Open · WTA · Round of 128
2 — 1
Sets
Monday, 14 January 2002 ·
hard
Panova T.1-6 6-3 10-8
Molik A.
Panova T.
16102
Molik A.
6381
Tatiana Panova defeated Alicia Molik 1-6 6-3 10-8 in the Australian Open round of 128 on hard. The result followed the form book — Tatiana Panova came in leading the head-to-head 2–1, defending last year's round of 128. Tatiana Panova extended the head-to-head to 3–1.
Key context
- Match story: Tatiana Panova dropped the opening set before beating Alicia Molik 1–6 6–3 10–8.
Head to head
2–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2005-01-17 | Australian Open | R32 | hard | Alicia Molik | 6-3 6-2 |
| 2002-09-16 | Tokyo | R16 | hard | Tatiana Panova | 7-5 6-4 |
| 2002-02-18 | Dubai | R32 | hard | Tatiana Panova | 6-0 5-7 6-4 |
Statistics
This season1st serve in·Even
61%
61%
1st serve points won·Clear edge
54%
66%
2nd serve points won·Slight edge
40%
46%
Service points won·Slight edge
49%
58%
Return points won·Even
40%
39%
Break points saved·Slight edge
51%
57%
Aces / match·Dominant
0.8
5.4
Double faults / match·Dominant
5.9
2.9
Averages over each player's completed matches in the selected window (12 vs 89). ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast