Jennifer Hopkins vs Irina Selyutina — Australian Open Round of 128
Australian Open · WTA · Round of 128
2 — 1
Sets
Monday, 14 January 2002 ·
hard
Hopkins J.6-2 0-6 6-2
Selyutina I.
Hopkins J.
6062
Selyutina I.
2621
Jennifer Hopkins defeated Irina Selyutina 6-2 0-6 6-2 in the Australian Open round of 128 on hard. The result followed the form book — Jennifer Hopkins came in leading the head-to-head 2–0, defending last year's round of 128. Jennifer Hopkins extended the head-to-head to 3–0.
Key context
- Match story: Jennifer Hopkins closed it out in three sets, 6–2 0–6 6–2.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2000-06-26 | Wimbledon | Q128 | grass | Jennifer Hopkins | 6-4 6-3 |
| 1999-10-04 | Albuquerque 50K | R32 | hard | Jennifer Hopkins | 6-1 6-3 |
Statistics
This season1st serve in·
55%
—
1st serve points won·
58%
—
2nd serve points won·
40%
—
Service points won·
50%
—
Return points won·
33%
—
Break points saved·
50%
—
Aces / match·
1.8
—
Double faults / match·
4.8
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast