Lukasz Kubot vs Jan Mertl — Czech Rep F6 Round of 16
Czech Rep F6 · ITF · Round of 16
2 — 0
Sets
Monday, 12 November 2001 ·
hard
Kubot L.6-3 6-1
Mertl J.
Kubot L.
662
Mertl J.
310
Lukasz Kubot defeated Jan Mertl 6-3 6-1 in the Czech Rep F6 round of 16 on hard. The result followed the form book — Lukasz Kubot came in leading the head-to-head 1–0. Lukasz Kubot extended the head-to-head to 2–0.
Key context
- Match story: Lukasz Kubot dropped just 4 games past Jan Mertl.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2004-11-01 | Czech Rep F5 | F | hard | Lukasz Kubot | 6-3 6-1 |
Statistics
This season1st serve in·Even
62%
62%
1st serve points won·Even
69%
73%
2nd serve points won·Even
48%
49%
Service points won·Even
61%
64%
Return points won·Even
36%
36%
Break points saved·Slight edge
58%
63%
Aces / match·Clear edge
5.1
7.0
Double faults / match·Dominant
4.7
2.8
Averages over each player's completed matches in the selected window (200 vs 128). ATP, WTA & Challenger.