Pete Sampras vs Bohdan Ulihrach — Australian Open Round of 64
Australian Open · ATP · Round of 64
3 — 1
Sets
Monday, 15 January 2001 ·
hard
Sampras P.7-6 7-6 4-6 7-5
Ulihrach B.
Sampras P.
77473
Ulihrach B.
66651
Pete Sampras defeated Bohdan Ulihrach 7-6 7-6 4-6 7-5 in the Australian Open round of 64 on hard. The result followed the form book — Pete Sampras came in leading the head-to-head 3–1, defending last year's semi-final. Pete Sampras extended the head-to-head to 4–1.
Key context
- Match story: Pete Sampras edged Bohdan Ulihrach in four tight sets (7–6 7–6 4–6 7–5).
Head to head
3–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-05-10 | Rome Masters | R64 | clay | Pete Sampras | 3-6 6-2 7-6 |
| 1998-10-26 | Stuttgart Masters | R16 | carpet | Pete Sampras | 6-3 6-3 |
| 1997-03-10 | Indian Wells Masters | R32 | hard | Bohdan Ulihrach | 7-6 7-5 |
| 1996-08-12 | Indianapolis | SF | hard | Pete Sampras | 6-1 6-4 |
Statistics
This season1st serve in·Even
60%
60%
1st serve points won·Slight edge
79%
68%
2nd serve points won·Even
52%
49%
Service points won·Slight edge
68%
60%
Return points won·Even
35%
37%
Break points saved·Slight edge
68%
58%
Aces / match·Dominant
13.3
3.3
Double faults / match·Dominant
5.4
3.4
Averages over each player's completed matches in the selected window (92 vs 158). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast