Pete Sampras vs Andrei Medvedev — Indian Wells Masters Round of 64
Indian Wells Masters · ATP · Round of 64
2 — 0
Sets
Monday, 13 March 2000 ·
hard
Sampras P.6-4 6-3
Medvedev A.
Sampras P.
662
Medvedev A.
430
Pete Sampras defeated Andrei Medvedev 6-4 6-3 in the Indian Wells Masters round of 64 on hard. The upset overturned the form book — Andrei Medvedev came in leading the head-to-head 2–1. Pete Sampras narrowed the head-to-head to 2–2.
Key context
- Match story: Pete Sampras closed it out in two sets, 6–4 6–3.
Head to head
1–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-05-24 | Roland Garros | R64 | clay | Andrei Medvedev | 7-5 1-6 6-4 6-3 |
| 1995-08-14 | Indianapolis | QF | hard | Pete Sampras | 6-2 6-2 |
| 1995-05-08 | Hamburg | SF | clay | Andrei Medvedev | 6-4 2-6 6-4 |
Statistics
This season1st serve in·Even
61%
58%
1st serve points won·Slight edge
79%
69%
2nd serve points won·Slight edge
53%
47%
Service points won·Slight edge
69%
60%
Return points won·Even
35%
39%
Break points saved·Slight edge
69%
63%
Aces / match·Dominant
13.1
5.2
Double faults / match·Dominant
5.5
3.4
Averages over each player's completed matches in the selected window (143 vs 60). ATP, WTA & Challenger.
Conditions
Court speed
Medium-slowfavours grinders
SlowFast