Alexandros Jakupovic vs Alex Halsey — Cyprus F1 Round of 32
Cyprus F1 · ITF · Round of 32
2 — 0
Sets
Monday, 8 November 1999 ·
clay
GBRAlex Halsey
Last 10 · pre-matchNo recent matches
Jakupovic A.6-3 7-5
Halsey A.
Jakupovic A.
672
Halsey A.
350
Alexandros Jakupovic defeated Alex Halsey 6-3 7-5 in the Cyprus F1 round of 32 on clay.
Key context
- Match story: Alexandros Jakupovic closed it out in two sets, 6–3 7–5.
Head to head
No previous meetings on record.