John Van Lottum vs Wayne Arthurs — Singapore Round of 32
Singapore · ATP · Round of 32
2 — 0
Sets
Monday, 11 October 1999 ·
hard
Van Lottum J.7-6 7-6
Arthurs W.
Van Lottum J.
772
Arthurs W.
660
John Van Lottum defeated Wayne Arthurs 7-6 7-6 in the Singapore round of 32 on hard. The upset overturned the form book — Wayne Arthurs came in leading the head-to-head 1–0. John Van Lottum claimed a first win over Wayne Arthurs in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: John Van Lottum won all two sets in tiebreaks against Wayne Arthurs.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2006-05-24 | Roland Garros | Q64 | clay | Wayne Arthurs | 7-6(2) 6-3 |
Statistics
This season1st serve in·Even
54%
56%
1st serve points won·Clear edge
68%
80%
2nd serve points won·Slight edge
49%
54%
Service points won·Slight edge
59%
69%
Return points won·Slight edge
37%
30%
Break points saved·Slight edge
58%
68%
Aces / match·Dominant
3.1
15.8
Double faults / match·Dominant
3.3
5.1
Averages over each player's completed matches in the selected window (109 vs 200). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast