Hicham Arazi vs Andrei Pavel — Bucharest Round of 32
Bucharest · ATP · Round of 32
2 — 0
Sets
Monday, 27 September 1999 ·
clay
Arazi H.7-6 6-3
Pavel A.
Arazi H.
762
Pavel A.
630
Hicham Arazi defeated Andrei Pavel 7-6 6-3 in the Bucharest round of 32 on clay. The upset overturned the form book — Andrei Pavel came in leading the head-to-head 2–0, defending last year's quarter-final. Hicham Arazi claimed a first win over Andrei Pavel in three meetings, narrowing the head-to-head to 2–1.
Key context
- Match story: Hicham Arazi closed it out in two sets, 7–6 6–3.
Head to head
0–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2001-07-30 | Canada Masters | R16 | hard | Andrei Pavel | 6-0 6-2 |
| 1995-07-31 | Kitzbuhel | R64 | clay | Andrei Pavel | 7-5 3-6 6-3 |
Statistics
This season1st serve in·Slight edge
59%
64%
1st serve points won·Even
68%
69%
2nd serve points won·Even
52%
49%
Service points won·Even
62%
62%
Return points won·Even
38%
37%
Break points saved·Even
60%
60%
Aces / match·Clear edge
3.8
5.4
Double faults / match·Slight edge
1.7
2.0
Averages over each player's completed matches in the selected window (200 vs 200). ATP, WTA & Challenger.
Conditions
Court speed
Slowlow bounce, long rallies
SlowFast