Patricio Arquez vs Rodolfo Rake — Bolivia F1 Round of 16
Bolivia F1 · ITF · Round of 16
2 — 1
Sets
Monday, 20 September 1999 ·
clay
Arquez P.3-6 6-1 6-4
Rake R.
Arquez P.
3662
Rake R.
6141
Patricio Arquez defeated Rodolfo Rake 3-6 6-1 6-4 in the Bolivia F1 round of 16 on clay. The upset overturned the form book — Rodolfo Rake came in leading the head-to-head 1–0. Patricio Arquez claimed a first win over Rodolfo Rake in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Patricio Arquez dropped the opening set before beating Rodolfo Rake 3–6 6–1 6–4.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-11-08 | Argentina F5 | R16 | clay | Rodolfo Rake | 5-7 6-0 6-2 |
Statistics
This season1st serve in·
54%
—
1st serve points won·
36%
—
2nd serve points won·
43%
—
Service points won·
39%
—
Return points won·
33%
—
Break points saved·
14%
—
Aces / match·
0.0
—
Double faults / match·
1.0
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.