Arnaud Clement vs Bohdan Ulihrach — Indianapolis Round of 64
Indianapolis · ATP · Round of 64
2 — 0
Sets
Monday, 16 August 1999 ·
hard
Clement A.6-4 6-4
Ulihrach B.
Clement A.
662
Ulihrach B.
440
Arnaud Clement defeated Bohdan Ulihrach 6-4 6-4 in the Indianapolis round of 64 on hard. The result followed the form book — Arnaud Clement came in defending last year's round of 32. Arnaud Clement extended the head-to-head to 2–1.
Key context
- Match story: Arnaud Clement edged a tight contest from start to finish — 6–4 6–4.
Head to head
1–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2001-05-14 | Hamburg Masters | R64 | clay | Bohdan Ulihrach | 7-5 6-2 |
| 2001-01-08 | Sydney | R32 | hard | Arnaud Clement | 6-1 3-0 |
Statistics
This season1st serve in·Even
57%
60%
1st serve points won·Even
72%
68%
2nd serve points won·Even
50%
48%
Service points won·Even
63%
60%
Return points won·Even
36%
38%
Break points saved·Even
60%
58%
Aces / match·Clear edge
5.2
3.2
Double faults / match·Clear edge
2.5
3.7
Averages over each player's completed matches in the selected window (200 vs 200). ATP, WTA & Challenger.