Michael Chang vs Guillaume Raoux — Los Angeles Round of 16
Los Angeles · ATP · Round of 16
2 — 0
Sets
Monday, 26 July 1999 ·
hard
Chang M.6-4 6-2
Raoux G.
Chang M.
662
Raoux G.
420
Michael Chang defeated Guillaume Raoux 6-4 6-2 in the Los Angeles round of 16 on hard. The upset overturned the form book — Guillaume Raoux came in defending last year's semi-final. Michael Chang extended the head-to-head to 3–2.
Key context
- Match story: Michael Chang dropped just 6 games past Guillaume Raoux.
Head to head
2–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1998-10-26 | Stuttgart Masters | R64 | carpet | Guillaume Raoux | 7-6 6-3 |
| 1998-01-19 | Australian Open | R64 | hard | Guillaume Raoux | 6-4 7-6 7-6 |
| 1996-01-15 | Australian Open | R32 | hard | Michael Chang | 6-2 6-2 7-6(6) |
| 1991-06-10 | Queen's Club | R16 | grass | Michael Chang | 7-5 6-2 |
Statistics
This season1st serve in·Even
56%
52%
1st serve points won·Even
70%
70%
2nd serve points won·Even
50%
54%
Service points won·Even
61%
62%
Return points won·Slight edge
39%
33%
Break points saved·Even
57%
60%
Aces / match·Slight edge
3.9
4.6
Double faults / match·Dominant
1.7
3.6
Averages over each player's completed matches in the selected window (189 vs 30). ATP, WTA & Challenger.