Bob Borella vs Larbi Rharnit — Austria F3 Round of 32
Austria F3 · ITF · Round of 32
2 — 0
Sets
Monday, 19 July 1999 ·
clay
Borella B.6-0 6-1
Rharnit L.
Borella B.
662
Rharnit L.
010
Bob Borella defeated Larbi Rharnit 6-0 6-1 in the Austria F3 round of 32 on clay.
Key context
- Match story: Bob Borella handed Larbi Rharnit a first-set bagel in a 6–0 6–1 win.
Head to head
No previous meetings on record.