Tatiana Panova vs Natalia Zvereva — Wimbledon Round of 64
Wimbledon · WTA · Round of 64
2 — 0
Sets
Monday, 21 June 1999 ·
grass
Panova T.6-4 7-5
Zvereva N.
Panova T.
672
Zvereva N.
450
Tatiana Panova defeated Natalia Zvereva 6-4 7-5 in the Wimbledon round of 64 on grass. The upset overturned the form book — Natalia Zvereva came in leading the head-to-head 1–0, defending last year's semi-final. Tatiana Panova claimed a first win over Natalia Zvereva in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Tatiana Panova edged Natalia Zvereva in two tight sets (6–4 7–5).
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1998-10-20 | Kremlin Cup | R32 | carpet | Natalia Zvereva | 6-3 6-2 |
Statistics
This season1st serve in·
61%
—
1st serve points won·
54%
—
2nd serve points won·
40%
—
Service points won·
49%
—
Return points won·
40%
—
Break points saved·
51%
—
Aces / match·
0.8
—
Double faults / match·
5.9
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast