Andrei Medvedev vs Byron Black — Roland Garros Round of 32
Roland Garros · ATP · Round of 32
3 — 1
Sets
Monday, 24 May 1999 ·
clay
Medvedev A.6-1 6-2 3-6 6-1
Black B.
Medvedev A.
66363
Black B.
12611
Andrei Medvedev defeated Byron Black 6-1 6-2 3-6 6-1 in the Roland Garros round of 32 on clay. The result followed the form book — Andrei Medvedev came in leading the head-to-head 1–0, defending last year's round of 128. Andrei Medvedev extended the head-to-head to 2–0.
Key context
- Match story: Andrei Medvedev closed it out in four sets, 6–1 6–2 3–6 6–1.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1996-02-12 | Dubai | R32 | hard | Andrei Medvedev | 6-4 6-1 |
Statistics
This season1st serve in·Slight edge
57%
62%
1st serve points won·Even
70%
68%
2nd serve points won·Even
47%
51%
Service points won·Even
60%
62%
Return points won·Even
39%
39%
Break points saved·Even
62%
58%
Aces / match·Clear edge
5.7
3.7
Double faults / match·Dominant
3.8
2.0
Averages over each player's completed matches in the selected window (101 vs 118). ATP, WTA & Challenger.
Conditions
Court speed
Slowlow bounce, long rallies
SlowFast