Greg Rusedski vs Petr Korda — Indian Wells Masters Round of 64
Indian Wells Masters · ATP · Round of 64
2 — 0
Sets
Monday, 8 March 1999 ·
hard
Rusedski G.6-3 6-4
Korda P.
Rusedski G.
662
Korda P.
340
Greg Rusedski defeated Petr Korda 6-3 6-4 in the Indian Wells Masters round of 64 on hard. The result followed the form book — Greg Rusedski came in leading the head-to-head 2–0, defending last year's final. Greg Rusedski extended the head-to-head to 3–0.
Key context
- Match story: Greg Rusedski closed it out in two sets, 6–3 6–4.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-02-22 | London | R16 | carpet | Greg Rusedski | 6-3 7-6 |
| 1997-09-29 | Basel | SF | hard | Greg Rusedski | 6-7 6-3 7-5 |
Statistics
This season1st serve in·Even
60%
57%
1st serve points won·Slight edge
78%
71%
2nd serve points won·Slight edge
53%
46%
Service points won·Slight edge
68%
61%
Return points won·Even
33%
36%
Break points saved·Even
68%
69%
Aces / match·Dominant
10.8
5.1
Double faults / match·Slight edge
4.9
5.5
Averages over each player's completed matches in the selected window (200 vs 17). ATP, WTA & Challenger.
Conditions
Court speed
Medium-slowfavours grinders
SlowFast