Karol Kucera vs Byron Black — Indian Wells Masters Round of 64
Indian Wells Masters · ATP · Round of 64
2 — 1
Sets
Monday, 8 March 1999 ·
hard
Kucera K.6-4 3-6 6-4
Black B.
Kucera K.
6362
Black B.
4641
Karol Kucera defeated Byron Black 6-4 3-6 6-4 in the Indian Wells Masters round of 64 on hard. The result followed the form book — Karol Kucera came in leading the head-to-head 4–0, defending last year's round of 32. Karol Kucera extended the head-to-head to 5–0.
Key context
- Match story: Karol Kucera closed it out in three sets, 6–4 3–6 6–4.
Head to head
4–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-02-15 | Rotterdam | R32 | hard | Karol Kucera | 6-1 6-1 |
| 1997-06-16 | Nottingham | R16 | grass | Karol Kucera | 7-5 6-3 |
| 1996-07-15 | Washington | R32 | hard | Karol Kucera | 6-2 6-0 |
| 1996-06-24 | Wimbledon | R64 | grass | Karol Kucera | 4-6 6-1 5-7 6-3 6-3 |
Statistics
This season1st serve in·Slight edge
56%
62%
1st serve points won·Even
72%
68%
2nd serve points won·Even
48%
51%
Service points won·Even
61%
62%
Return points won·Even
40%
39%
Break points saved·Even
57%
58%
Aces / match·Clear edge
5.6
3.7
Double faults / match·Dominant
4.7
2.0
Averages over each player's completed matches in the selected window (200 vs 118). ATP, WTA & Challenger.
Conditions
Court speed
Medium-slowfavours grinders
SlowFast