Alexandra Stevenson vs Tara Snyder — Indian Wells Round of 64
Indian Wells · WTA · Round of 64
2 — 0
Sets
Friday, 5 March 1999 ·
hard
Stevenson A.7-5 6-4
Snyder T.
Stevenson A.
762
Snyder T.
540
Alexandra Stevenson defeated Tara Snyder 7-5 6-4 in the Indian Wells round of 64 on hard. The result followed the form book — Alexandra Stevenson came in leading the head-to-head 2–0. Alexandra Stevenson extended the head-to-head to 3–0.
Key context
- Match story: Alexandra Stevenson edged Tara Snyder in two tight sets (7–5 6–4).
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2006-08-06 | Los Angeles | Q16 | hard | Alexandra Stevenson | 6-1 1-0 |
| 1998-02-10 | Midland 50K | SF | hard | Alexandra Stevenson | 6-2 7-6 |
Statistics
This season1st serve in·Clear edge
57%
69%
1st serve points won·Clear edge
66%
42%
2nd serve points won·Slight edge
40%
29%
Service points won·Clear edge
55%
38%
Return points won·Slight edge
37%
44%
Break points saved·Dominant
61%
0%
Aces / match·Clear edge
4.5
2.0
Double faults / match·Dominant
6.0
3.0
Averages over each player's completed matches in the selected window (26 vs 1). ATP, WTA & Challenger.
Conditions
Court speed
Medium-slowfavours grinders
SlowFast