Kveta Peschke vs Tatiana Panova — Indian Wells Round of 64
Indian Wells · WTA · Round of 64
2 — 0
Sets
Friday, 5 March 1999 ·
hard
Peschke K.6-4 6-1
Panova T.
Peschke K.
662
Panova T.
410
Kveta Peschke defeated Tatiana Panova 6-4 6-1 in the Indian Wells round of 64 on hard. The upset overturned the form book — Tatiana Panova came in leading the head-to-head 1–0, defending last year's round of 32. Kveta Peschke claimed a first win over Tatiana Panova in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Kveta Peschke dropped just 5 games past Tatiana Panova.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2005-07-18 | Cincinnati | R32 | hard | Tatiana Panova | 6-4 7-6 |
Statistics
This season1st serve in·Even
60%
61%
1st serve points won·Slight edge
59%
54%
2nd serve points won·Even
42%
40%
Service points won·Even
52%
49%
Return points won·Even
44%
40%
Break points saved·Even
53%
51%
Aces / match·Even
0.9
0.8
Double faults / match·Dominant
3.8
5.9
Averages over each player's completed matches in the selected window (34 vs 12). ATP, WTA & Challenger.
Conditions
Court speed
Medium-slowfavours grinders
SlowFast