Amelie Mauresmo vs Dominique Monami — Paris Semi-final
Paris · WTA · Semi-final
2 — 0
Sets
Monday, 22 February 1999 ·
carpet
Mauresmo A.6-0 7-6
Monami D.
Mauresmo A.
672
Monami D.
060
Amelie Mauresmo defeated Dominique Monami 6-0 7-6 in the Paris semi-final on carpet. The result followed the form book — Amelie Mauresmo came in leading the head-to-head 2–1. Amelie Mauresmo extended the head-to-head to 3–1.
Key context
- Match story: Amelie Mauresmo handed Dominique Monami a first-set bagel in a 6–0 7–6 win.
Head to head
2–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-01-18 | Australian Open | QF | hard | Amelie Mauresmo | 6-3 7-6 |
| 1998-10-12 | Zurich | R16 | hard | Dominique Monami | 6-3 6-4 |
| 1998-05-11 | Berlin | R64 | grass | Amelie Mauresmo | 3-6 6-4 7-5 |
Statistics
This season1st serve in·
62%
—
1st serve points won·
68%
—
2nd serve points won·
45%
—
Service points won·
59%
—
Return points won·
46%
—
Break points saved·
59%
—
Aces / match·
3.5
—
Double faults / match·
4.6
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.