Mikael Tillstrom vs Andrei Cherkasov — St. Petersburg Round of 32
St. Petersburg · ATP · Round of 32
2 — 1
Sets
Monday, 8 February 1999 ·
carpet
Tillstrom M.3-6 6-4 6-4
Cherkasov A.
Tillstrom M.
3662
Cherkasov A.
6441
Mikael Tillstrom defeated Andrei Cherkasov 3-6 6-4 6-4 in the St. Petersburg round of 32 on carpet. The result followed the form book — Mikael Tillstrom came in leading the head-to-head 3–1, defending last year's round of 32. Mikael Tillstrom extended the head-to-head to 4–1.
Key context
- Match story: Mikael Tillstrom dropped the opening set before beating Andrei Cherkasov 3–6 6–4 6–4.
Head to head
3–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2000-01-03 | Doha | R16 | hard | Mikael Tillstrom | 7-6 6-4 |
| 1997-01-01 | Adelaide | QF | hard | Mikael Tillstrom | 6-2 6-4 |
| 1996-12-30 | Adelaide | QF | hard | Mikael Tillstrom | 6-2 6-4 |
| 1993-09-13 | Bucharest | R32 | clay | Andrei Cherkasov | 6-3 6-0 |
Statistics
This season1st serve in·Even
61%
58%
1st serve points won·Even
67%
66%
2nd serve points won·Even
48%
46%
Service points won·Even
60%
58%
Return points won·Even
39%
43%
Break points saved·Even
58%
56%
Aces / match·Clear edge
4.0
2.0
Double faults / match·Clear edge
3.3
4.3
Averages over each player's completed matches in the selected window (64 vs 12). ATP, WTA & Challenger.
Conditions
Court speed
Mediumbalanced pace
SlowFast