Chanda Rubin vs Natalia Zvereva — Australian Open Round of 32
Australian Open · WTA · Round of 32
2 — 1
Sets
Monday, 18 January 1999 ·
hard
Rubin C.7-6 4-6 6-4
Zvereva N.
Rubin C.
7462
Zvereva N.
6641
Chanda Rubin defeated Natalia Zvereva 7-6 4-6 6-4 in the Australian Open round of 32 on hard. The result followed the form book — Chanda Rubin came in leading the head-to-head 1–0, defending last year's round of 128. Chanda Rubin extended the head-to-head to 2–0.
Key context
- Match story: Chanda Rubin edged Natalia Zvereva in three tight sets (7–6 4–6 6–4).
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2000-05-29 | Roland Garros | R16 | clay | Chanda Rubin | 6-4 7-5 |
Statistics
This season1st serve in·
62%
—
1st serve points won·
60%
—
2nd serve points won·
48%
—
Service points won·
55%
—
Return points won·
46%
—
Break points saved·
52%
—
Aces / match·
1.5
—
Double faults / match·
2.6
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast