Fabrice Santoro vs Guillaume Raoux — Australian Open Round of 64
Australian Open · ATP · Round of 64
3 — 2
Sets
Monday, 18 January 1999 ·
hard
Santoro F.6-4 1-6 6-2 4-6 6-3
Raoux G.
Santoro F.
616463
Raoux G.
462632
Fabrice Santoro defeated Guillaume Raoux 6-4 1-6 6-2 4-6 6-3 in the Australian Open round of 64 on hard. The result followed the form book — Fabrice Santoro came in leading the head-to-head 1–0, defending last year's round of 32. Fabrice Santoro extended the head-to-head to 2–0.
Key context
- Match story: Fabrice Santoro closed it out in five sets, 6–4 1–6 6–2 4–6 6–3.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1990-05-28 | Roland Garros | R128 | clay | Fabrice Santoro | 6-1 6-4 6-4 |
Statistics
This season1st serve in·Slight edge
57%
51%
1st serve points won·Even
69%
70%
2nd serve points won·Even
51%
54%
Service points won·Even
61%
62%
Return points won·Slight edge
38%
32%
Break points saved·Even
60%
60%
Aces / match·Even
4.2
4.6
Double faults / match·Dominant
1.8
3.8
Averages over each player's completed matches in the selected window (200 vs 30). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast