Janet Lee vs Lenka Nemeckova — Australian Open Round of 128
Australian Open · WTA · Round of 128
2 — 0
Sets
Monday, 18 January 1999 ·
hard
Lee J.6-0 6-2
Nemeckova L.
Lee J.
662
Nemeckova L.
020
Janet Lee defeated Lenka Nemeckova 6-0 6-2 in the Australian Open round of 128 on hard. The result followed the form book — Janet Lee came in leading the head-to-head 1–0, defending last year's round of 128. Janet Lee extended the head-to-head to 2–0.
Key context
- Match story: Janet Lee handed Lenka Nemeckova a first-set bagel in a 6–0 6–2 win.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-09-27 | Santa Clara 75K | R16 | hard | Janet Lee | 6-0 5-7 7-5 |
Statistics
This season1st serve in·
62%
—
1st serve points won·
59%
—
2nd serve points won·
33%
—
Service points won·
49%
—
Return points won·
42%
—
Break points saved·
43%
—
Aces / match·
5.0
—
Double faults / match·
1.0
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast