Nicolas Kiefer vs Cecil Mamiit — Australian Open Round of 64
Australian Open · ATP · Round of 64
3 — 0
Sets
Monday, 18 January 1999 ·
hard
Kiefer N.6-2 7-5 7-6
Mamiit C.
Kiefer N.
6773
Mamiit C.
2560
Nicolas Kiefer defeated Cecil Mamiit 6-2 7-5 7-6 in the Australian Open round of 64 on hard. The result followed the form book — Nicolas Kiefer came in leading the head-to-head 1–0, defending last year's quarter-final. Nicolas Kiefer extended the head-to-head to 2–0.
Key context
- Match story: Nicolas Kiefer closed it out in three sets, 6–2 7–5 7–6.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-09-13 | Tashkent | QF | hard | Nicolas Kiefer | 6-1 7-5 |
Statistics
This season1st serve in·Slight edge
53%
58%
1st serve points won·Slight edge
76%
67%
2nd serve points won·Even
50%
48%
Service points won·Slight edge
64%
59%
Return points won·Even
39%
38%
Break points saved·Even
60%
57%
Aces / match·Dominant
7.5
3.2
Double faults / match·Slight edge
3.4
2.9
Averages over each player's completed matches in the selected window (200 vs 126). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast