Christian Ruud vs Lucas Arnold Ker — Australian Open Round of 128
Australian Open · ATP · Round of 128
3 — 1
Sets
Monday, 18 January 1999 ·
hard
Ruud C.7-5 3-6 6-4 6-2
Arnold Ker L.
Ruud C.
73663
Arnold Ker L.
56421
Christian Ruud defeated Lucas Arnold Ker 7-5 3-6 6-4 6-2 in the Australian Open round of 128 on hard. The result followed the form book — Christian Ruud came in leading the head-to-head 1–0, defending last year's round of 128. Christian Ruud extended the head-to-head to 2–0.
Key context
- Match story: Christian Ruud closed it out in four sets, 7–5 3–6 6–4 6–2.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-04-19 | Orlando | R16 | clay | Christian Ruud | 3-6 7-6 6-2 |
Statistics
This season1st serve in·Even
60%
59%
1st serve points won·Even
64%
63%
2nd serve points won·Slight edge
49%
39%
Service points won·Slight edge
58%
53%
Return points won·Even
40%
41%
Break points saved·Slight edge
55%
60%
Aces / match·Even
2.9
2.7
Double faults / match·Dominant
2.9
5.5
Averages over each player's completed matches in the selected window (67 vs 6). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast