Andrew Ilie vs Christian Ruud — Australian Open Round of 32
Australian Open · ATP · Round of 32
3 — 0
Sets
Monday, 18 January 1999 ·
hard
Ilie A.6-2 6-2 6-4
Ruud C.
Ilie A.
6663
Ruud C.
2240
Andrew Ilie defeated Christian Ruud 6-2 6-2 6-4 in the Australian Open round of 32 on hard. The result followed the form book — Andrew Ilie came in leading the head-to-head 1–0, defending last year's round of 32. Andrew Ilie extended the head-to-head to 2–0.
Key context
- Match story: Andrew Ilie closed it out in three sets, 6–2 6–2 6–4.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-02-15 | Memphis | R32 | hard | Andrew Ilie | 6-7 6-2 6-3 |
Statistics
This season1st serve in·Slight edge
54%
59%
1st serve points won·Even
69%
65%
2nd serve points won·Even
49%
49%
Service points won·Even
60%
58%
Return points won·Slight edge
36%
41%
Break points saved·Slight edge
60%
55%
Aces / match·Clear edge
5.2
2.9
Double faults / match·Slight edge
3.4
2.9
Averages over each player's completed matches in the selected window (157 vs 67). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast