Tim Henman vs Sandon Stolle — Australian Open Round of 64
Australian Open · ATP · Round of 64
3 — 2
Sets
Monday, 18 January 1999 ·
hard
Henman T.4-6 7-5 4-6 6-1 6-4
Stolle S.
Henman T.
474663
Stolle S.
656142
Tim Henman defeated Sandon Stolle 4-6 7-5 4-6 6-1 6-4 in the Australian Open round of 64 on hard.
Key context
- Match story: Tim Henman dropped the opening set before beating Sandon Stolle 4–6 7–5 4–6 6–1 6–4.
Head to head
No previous meetings on record.
Statistics
This season1st serve in·Even
61%
60%
1st serve points won·Slight edge
73%
79%
2nd serve points won·Slight edge
52%
44%
Service points won·Even
65%
64%
Return points won·Even
39%
37%
Break points saved·Slight edge
62%
53%
Aces / match·Dominant
5.4
8.7
Double faults / match·Dominant
3.5
5.3
Averages over each player's completed matches in the selected window (200 vs 6). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast