Bohdan Ulihrach vs Andrei Cherkasov — Australian Open Round of 64
Australian Open · ATP · Round of 64
3 — 2
Sets
Monday, 18 January 1999 ·
hard
Ulihrach B.7-6 4-6 6-7 6-4 6-4
Cherkasov A.
Ulihrach B.
746663
Cherkasov A.
667442
Bohdan Ulihrach defeated Andrei Cherkasov 7-6 4-6 6-7 6-4 6-4 in the Australian Open round of 64 on hard. The upset overturned the form book — Andrei Cherkasov came in leading the head-to-head 1–0. Bohdan Ulihrach claimed a first win over Andrei Cherkasov in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Bohdan Ulihrach edged Andrei Cherkasov in five tight sets (7–6 4–6 6–7 6–4 6–4).
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1993-08-02 | Prague | R32 | clay | Andrei Cherkasov | 6-1 7-5 |
Statistics
This season1st serve in·Even
60%
58%
1st serve points won·Even
68%
67%
2nd serve points won·Even
48%
47%
Service points won·Even
60%
59%
Return points won·Slight edge
38%
43%
Break points saved·Even
58%
54%
Aces / match·Slight edge
3.1
1.9
Double faults / match·Even
3.7
3.8
Averages over each player's completed matches in the selected window (200 vs 12). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast