Wayne Arthurs vs Karol Kucera — Stockholm Round of 32
Stockholm · ATP · Round of 32
2 — 0
Sets
Monday, 9 November 1998 ·
hard
Arthurs W.7-6 7-6
Kucera K.
Arthurs W.
772
Kucera K.
660
Wayne Arthurs defeated Karol Kucera 7-6 7-6 in the Stockholm round of 32 on hard. The upset overturned the form book — Karol Kucera came in leading the head-to-head 2–0, defending last year's quarter-final. Wayne Arthurs claimed a first win over Karol Kucera in three meetings, narrowing the head-to-head to 2–1.
Key context
- Match story: Wayne Arthurs won all two sets in tiebreaks against Karol Kucera.
Head to head
0–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2003-02-24 | Copenhagen | SF | carpet | Karol Kucera | 6-2 6-4 |
| 1999-07-26 | Kitzbuhel | R32 | clay | Karol Kucera | 6-3 6-4 |
Statistics
This season1st serve in·Even
56%
56%
1st serve points won·Slight edge
80%
72%
2nd serve points won·Slight edge
54%
48%
Service points won·Slight edge
69%
61%
Return points won·Slight edge
30%
40%
Break points saved·Slight edge
68%
57%
Aces / match·Dominant
15.8
5.6
Double faults / match·Slight edge
5.1
4.7
Averages over each player's completed matches in the selected window (200 vs 200). ATP, WTA & Challenger.
Conditions
Court speed
Mediumbalanced pace
SlowFast