Magnus Norman vs John Van Lottum — Ostrava Round of 32
Ostrava · ATP · Round of 32
2 — 0
Sets
Monday, 19 October 1998 ·
carpet
Norman M.7-6 7-6
Van Lottum J.
Norman M.
772
Van Lottum J.
660
Magnus Norman defeated John Van Lottum 7-6 7-6 in the Ostrava round of 32 on carpet. The result followed the form book — Magnus Norman came in leading the head-to-head 1–0, defending last year's final. Magnus Norman extended the head-to-head to 2–0.
Key context
- Match story: Magnus Norman won all two sets in tiebreaks against John Van Lottum.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-01-18 | Australian Open | R128 | hard | Magnus Norman | 6-4 5-7 2-6 6-2 7-5 |
Statistics
This season1st serve in·Slight edge
61%
54%
1st serve points won·Even
71%
69%
2nd serve points won·Even
50%
49%
Service points won·Even
63%
60%
Return points won·Even
39%
36%
Break points saved·Even
61%
59%
Aces / match·Clear edge
5.8
3.3
Double faults / match·Clear edge
2.3
3.3
Averages over each player's completed matches in the selected window (200 vs 145). ATP, WTA & Challenger.