Arnaud Clement vs Paul Haarhuis — Indianapolis Round of 64
Indianapolis · ATP · Round of 64
2 — 0
Sets
Monday, 17 August 1998 ·
hard
Clement A.6-4 6-4
Haarhuis P.
Clement A.
662
Haarhuis P.
440
Arnaud Clement defeated Paul Haarhuis 6-4 6-4 in the Indianapolis round of 64 on hard. The result followed the form book — Arnaud Clement came in leading the head-to-head 1–0. Arnaud Clement extended the head-to-head to 2–0.
Key context
- Match story: Arnaud Clement edged a tight contest from start to finish — 6–4 6–4.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-04-12 | Barcelona | R64 | clay | Arnaud Clement | 6-4 6-7 6-4 |
Statistics
This season1st serve in·Even
57%
59%
1st serve points won·Even
72%
71%
2nd serve points won·Even
50%
49%
Service points won·Even
63%
62%
Return points won·Even
36%
37%
Break points saved·Even
60%
63%
Aces / match·Even
5.2
5.6
Double faults / match·Even
2.5
2.7
Averages over each player's completed matches in the selected window (200 vs 59). ATP, WTA & Challenger.