Byron Black vs Sebastien Lareau — Hong Kong Semi-final
Hong Kong · ATP · Semi-final
2 — 1
Sets
Monday, 6 April 1998 ·
hard
Black B.6-7 7-5 7-6
Lareau S.
Black B.
6772
Lareau S.
7561
Byron Black defeated Sebastien Lareau 6-7 7-5 7-6 in the Hong Kong semi-final on hard. The upset overturned the form book — Sebastien Lareau came in leading the head-to-head 1–0, defending last year's quarter-final, but Byron Black had been the form player, winning 1 of their last 4 on hard. Byron Black claimed a first win over Sebastien Lareau in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Byron Black dropped the opening set before beating Sebastien Lareau 6–7 7–5 7–6.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-04-12 | Tokyo | R32 | hard | Sebastien Lareau | 6-3 7-5 |
Statistics
This season1st serve in·Even
61%
63%
1st serve points won·Even
68%
70%
2nd serve points won·Even
52%
48%
Service points won·Even
62%
62%
Return points won·Even
40%
36%
Break points saved·Even
60%
62%
Aces / match·Clear edge
3.7
6.4
Double faults / match·Clear edge
2.2
3.5
Averages over each player's completed matches in the selected window (180 vs 93). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast