Bohdan Ulihrach vs Marcelo Filippini — Indian Wells Masters Round of 64
Indian Wells Masters · ATP · Round of 64
2 — 0
Sets
Monday, 9 March 1998 ·
hard
Ulihrach B.6-4 6-0
Filippini M.
Ulihrach B.
662
Filippini M.
400
Bohdan Ulihrach defeated Marcelo Filippini 6-4 6-0 in the Indian Wells Masters round of 64 on hard. The result followed the form book — Bohdan Ulihrach came in leading the head-to-head 1–0, defending last year's final. Bohdan Ulihrach extended the head-to-head to 2–0.
Key context
- Match story: Bohdan Ulihrach handed Marcelo Filippini a second-set bagel in a 6–4 6–0 win.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2000-07-24 | Kitzbuhel | R64 | clay | Bohdan Ulihrach | 6-1 6-3 |
Statistics
This season1st serve in·Slight edge
60%
67%
1st serve points won·Slight edge
68%
62%
2nd serve points won·Even
48%
51%
Service points won·Even
60%
58%
Return points won·Even
38%
37%
Break points saved·Even
58%
58%
Aces / match·Slight edge
3.1
1.9
Double faults / match·Dominant
3.7
1.9
Averages over each player's completed matches in the selected window (200 vs 39). ATP, WTA & Challenger.
Conditions
Court speed
Medium-slowfavours grinders
SlowFast