Jan Siemerink vs Bohdan Ulihrach — London Round of 16
London · ATP · Round of 16
2 — 1
Sets
Monday, 23 February 1998 ·
carpet
Siemerink J.6-3 6-7 6-4
Ulihrach B.
Siemerink J.
6662
Ulihrach B.
3741
Jan Siemerink defeated Bohdan Ulihrach 6-3 6-7 6-4 in the London round of 16 on carpet. The result followed the form book — Jan Siemerink came in leading the head-to-head 1–0. Jan Siemerink extended the head-to-head to 2–0.
Key context
- Match story: Jan Siemerink closed it out in three sets, 6–3 6–7 6–4.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1995-07-24 | Amsterdam | QF | clay | Jan Siemerink | 6-3 3-6 6-3 |
Statistics
This season1st serve in·Even
56%
60%
1st serve points won·Slight edge
76%
68%
2nd serve points won·Even
50%
48%
Service points won·Even
64%
60%
Return points won·Even
34%
38%
Break points saved·Slight edge
65%
58%
Aces / match·Dominant
7.3
3.1
Double faults / match·Dominant
5.3
3.7
Averages over each player's completed matches in the selected window (151 vs 200). ATP, WTA & Challenger.