Petr Korda vs Scott Draper — Australian Open Round of 64
Australian Open · ATP · Round of 64
3 — 0
Sets
Monday, 19 January 1998 ·
hard
Korda P.7-6 6-3 6-3
Draper S.
Korda P.
7663
Draper S.
6330
Petr Korda defeated Scott Draper 7-6 6-3 6-3 in the Australian Open round of 64 on hard. The result followed the form book — Petr Korda came in leading the head-to-head 1–0, defending last year's round of 128. Petr Korda extended the head-to-head to 2–0.
Key context
- Match story: Petr Korda closed it out in three sets, 7–6 6–3 6–3.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1998-03-09 | Indian Wells Masters | R32 | hard | Petr Korda | 6-3 3-6 6-0 |
Statistics
This season1st serve in·Even
53%
57%
1st serve points won·Even
73%
72%
2nd serve points won·Even
48%
52%
Service points won·Even
61%
63%
Return points won·Slight edge
39%
34%
Break points saved·Even
61%
60%
Aces / match·Clear edge
5.2
6.9
Double faults / match·Dominant
5.4
2.8
Averages over each player's completed matches in the selected window (71 vs 119). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast