Guillaume Raoux vs Wayne Black — Australian Open Round of 32
Australian Open · ATP · Round of 32
3 — 0
Sets
Monday, 19 January 1998 ·
hard
Raoux G.6-3 6-2 7-5
Black W.
Raoux G.
6673
Black W.
3250
Guillaume Raoux defeated Wayne Black 6-3 6-2 7-5 in the Australian Open round of 32 on hard. The result followed the form book — Guillaume Raoux came in defending last year's round of 64.
Key context
- Match story: Guillaume Raoux closed it out in three sets, 6–3 6–2 7–5.
Head to head
No previous meetings on record.
Statistics
This season1st serve in·Even
54%
57%
1st serve points won·Slight edge
71%
65%
2nd serve points won·Even
54%
51%
Service points won·Even
63%
59%
Return points won·Slight edge
34%
39%
Break points saved·Slight edge
62%
56%
Aces / match·Slight edge
4.2
3.0
Double faults / match·Slight edge
3.0
2.4
Averages over each player's completed matches in the selected window (81 vs 100). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast