Guillaume Raoux vs Daniel Nestor — Australian Open Round of 128
Australian Open · ATP · Round of 128
3 — 0
Sets
Monday, 13 January 1997 ·
hard
Raoux G.7-6 6-2 6-2
Nestor D.
Raoux G.
7663
Nestor D.
6220
Guillaume Raoux defeated Daniel Nestor 7-6 6-2 6-2 in the Australian Open round of 128 on hard. The result followed the form book — Guillaume Raoux came in leading the head-to-head 1–0, defending last year's round of 32. Guillaume Raoux extended the head-to-head to 2–0.
Key context
- Match story: Guillaume Raoux closed it out in three sets, 7–6 6–2 6–2.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1997-04-07 | Hong Kong | R32 | hard | Guillaume Raoux | 7-6 7-6 |
Statistics
This season1st serve in·Slight edge
55%
60%
1st serve points won·Even
72%
75%
2nd serve points won·Slight edge
53%
48%
Service points won·Even
64%
64%
Return points won·Even
34%
34%
Break points saved·Even
61%
59%
Aces / match·Dominant
4.5
8.9
Double faults / match·Dominant
2.9
5.7
Averages over each player's completed matches in the selected window (131 vs 113). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast