Tim Henman vs Guillaume Raoux — Australian Open Round of 64
Australian Open · ATP · Round of 64
3 — 0
Sets
Monday, 13 January 1997 ·
hard
Henman T.6-3 6-3 6-4
Raoux G.
Henman T.
6663
Raoux G.
3340
Tim Henman defeated Guillaume Raoux 6-3 6-3 6-4 in the Australian Open round of 64 on hard. The result followed the form book — Tim Henman came in leading the head-to-head 3–1, defending last year's round of 64. Tim Henman extended the head-to-head to 4–1.
Key context
- Match story: Tim Henman closed it out in three sets, 6–3 6–3 6–4.
Head to head
3–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-07-26 | Los Angeles | R32 | hard | Guillaume Raoux | 6-4 7-6 |
| 1998-07-27 | Los Angeles | SF | hard | Tim Henman | 7-5 6-3 |
| 1998-01-05 | Doha | R16 | hard | Tim Henman | 7-5 6-4 |
| 1997-10-13 | Lyon | R32 | clay | Tim Henman | 6-1 1-0 |
Statistics
This season1st serve in·Slight edge
61%
55%
1st serve points won·Even
73%
73%
2nd serve points won·Even
52%
53%
Service points won·Even
65%
64%
Return points won·Even
39%
35%
Break points saved·Even
61%
61%
Aces / match·Slight edge
5.4
4.6
Double faults / match·Slight edge
3.5
2.9
Averages over each player's completed matches in the selected window (200 vs 131). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast