Karol Kucera vs Paul Haarhuis — Australian Open Round of 128
Australian Open · ATP · Round of 128
3 — 2
Sets
Monday, 13 January 1997 ·
hard
Kucera K.6-1 2-6 6-3 4-6 6-4
Haarhuis P.
Kucera K.
626463
Haarhuis P.
163642
Karol Kucera defeated Paul Haarhuis 6-1 2-6 6-3 4-6 6-4 in the Australian Open round of 128 on hard. The result followed the form book — Karol Kucera came in defending last year's round of 32. Karol Kucera extended the head-to-head to 2–1.
Key context
- Match story: Karol Kucera came through a tight passage before pulling clear — 6–1 2–6 6–3 4–6 6–4.
Head to head
1–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-03-15 | Miami Masters | R64 | hard | Karol Kucera | 6-0 6-2 |
| 1993-02-22 | Rotterdam | R32 | hard | Paul Haarhuis | 5-7 6-4 6-2 |
Statistics
This season1st serve in·Even
56%
59%
1st serve points won·Even
72%
71%
2nd serve points won·Even
48%
49%
Service points won·Even
61%
62%
Return points won·Even
40%
37%
Break points saved·Slight edge
57%
62%
Aces / match·Even
5.6
5.6
Double faults / match·Dominant
4.7
2.8
Averages over each player's completed matches in the selected window (200 vs 104). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast