Jan Siemerink vs Paul Haarhuis — Amsterdam Round of 32
Amsterdam · ATP · Round of 32
2 — 0
Sets
Monday, 24 July 1995 ·
clay
Siemerink J.6-3 6-3
Haarhuis P.
Siemerink J.
662
Haarhuis P.
330
Jan Siemerink defeated Paul Haarhuis 6-3 6-3 in the Amsterdam round of 32 on clay. The result followed the form book — Jan Siemerink came in leading the head-to-head 2–0. Jan Siemerink extended the head-to-head to 3–0.
Key context
- Match story: Jan Siemerink dropped just 6 games past Paul Haarhuis.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-06-07 | Halle | R32 | grass | Jan Siemerink | 4-6 6-3 6-4 |
| 1995-08-21 | Long Island | R16 | hard | Jan Siemerink | 7-6(5) 6-4 |
Statistics
This season1st serve in·Even
56%
59%
1st serve points won·Even
75%
71%
2nd serve points won·Even
50%
49%
Service points won·Even
64%
62%
Return points won·Even
34%
37%
Break points saved·Even
65%
62%
Aces / match·Clear edge
7.3
5.6
Double faults / match·Dominant
5.2
2.7
Averages over each player's completed matches in the selected window (199 vs 106). ATP, WTA & Challenger.